Optimal. Leaf size=70 \[ \frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^4(c+d x)}}{\sqrt{a}}\right )}{2 \sqrt{a} d}-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d} \]
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Rubi [A] time = 0.0989119, antiderivative size = 70, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3229, 807, 266, 63, 208} \[ \frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^4(c+d x)}}{\sqrt{a}}\right )}{2 \sqrt{a} d}-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d} \]
Antiderivative was successfully verified.
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Rule 3229
Rule 807
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\cot ^3(c+d x)}{\sqrt{a+b \sin ^4(c+d x)}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1-x}{x^2 \sqrt{a+b x^2}} \, dx,x,\sin ^2(c+d x)\right )}{2 d}\\ &=-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d}-\frac{\operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x^2}} \, dx,x,\sin ^2(c+d x)\right )}{2 d}\\ &=-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d}-\frac{\operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,\sin ^4(c+d x)\right )}{4 d}\\ &=-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d}-\frac{\operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sin ^4(c+d x)}\right )}{2 b d}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^4(c+d x)}}{\sqrt{a}}\right )}{2 \sqrt{a} d}-\frac{\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d}\\ \end{align*}
Mathematica [A] time = 0.0815787, size = 66, normalized size = 0.94 \[ \frac{\sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a+b \sin ^4(c+d x)}}{\sqrt{a}}\right )-\csc ^2(c+d x) \sqrt{a+b \sin ^4(c+d x)}}{2 a d} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.71, size = 0, normalized size = 0. \begin{align*} \int{ \left ( \cot \left ( dx+c \right ) \right ) ^{3}{\frac{1}{\sqrt{a+b \left ( \sin \left ( dx+c \right ) \right ) ^{4}}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.54301, size = 640, normalized size = 9.14 \begin{align*} \left [\frac{{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sqrt{a} \log \left (\frac{8 \,{\left (b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + 2 \, \sqrt{b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b} \sqrt{a} + 2 \, a + b\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1}\right ) + 2 \, \sqrt{b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b}}{4 \,{\left (a d \cos \left (d x + c\right )^{2} - a d\right )}}, -\frac{{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b} \sqrt{-a}}{a}\right ) - \sqrt{b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b}}{2 \,{\left (a d \cos \left (d x + c\right )^{2} - a d\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cot ^{3}{\left (c + d x \right )}}{\sqrt{a + b \sin ^{4}{\left (c + d x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cot \left (d x + c\right )^{3}}{\sqrt{b \sin \left (d x + c\right )^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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